2/t^2-5/2t

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Solution for 2/t^2-5/2t equation: 


D( t )

t^2 = 0

t^2 = 0

t^2 = 0

1*t^2 = 0 // : 1

t^2 = 0

t = 0

t in (-oo:0) U (0:+oo)

2/(t^2)-((5/2)*t) = 0

(-5/2)*t+2/(t^2) = 0

2*t^-2-5/2*t = 0

t*(2*t^-3-5/2) = 0

2*t^-3 = 5/2 // : 2

t^-3 = 5/4

-3 < 0

1/(t^3) = 5/4 // * t^3

1 = 5/4*t^3 // : 5/4

4/5 = t^3

t^3 = 4/5 // ^ 1/3

t = (4/5)^(1/3)

t = 0

t = 0

t in { 0} 

t = (4/5)^(1/3)

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